Posted by **Ren** on Thursday, March 25, 2010 at 4:36pm.

How do I find the value of d^2y/dx^2 for the function defined implicitly by xy^2 + y = 2 at the point (1,-2)?

- Math - Implict differentiation -
**bobpursley**, Thursday, March 25, 2010 at 5:48pm
xy^2+y=2

y^2 dx + 2xy dy+dy=0

dy/dx ( 2xy+1)=y^2

dy/dx= y^2(1/(2xy+1)

dy"/dx"= 2y/(2xy+1) -y^2/(2xy+1)^2 * (2y*xdy/dx+2y)

Put for dy/dx y^2/(2xy+1)

then put number (1,-2)

CHECK MY WORK, I have a headache (Elm pollen).

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