Posted by Me on Thursday, March 25, 2010 at 12:57pm.
All you have to do is multiply parts of the 2500 by .08 and .12 then find which amount is the same.
EXP 1250 * .08 = 100 1250 * .12 = 150 since those don't match go to 1300*.08 and 1200*.12 and so on untill you find the same answer
Let the amount invested at 8% be x
then the amount invested at 12% is 2500-x
.08x = .12(2500-x)
times a 100
8x = 12(2500-x)
8x = 30000 - 12x
20x = 30000
x = 1500
So John investe $1500 at 8% and $1000 at 12%
Check: .08(1500) = 120 , and .12(1000) = 120
would you really have to multiply .08 and .12 by 100 or could you leave it the way it is?
You could just work with the decimals.
I just like to work with whole numbers rather than decimals or fractions.
That is because calculators did not exist for most of my teaching career and we had to do calculations in our heads or with pencil and paper.
I see well think you for showing me an easier and faster way to figure that problem out. I was taught the long way on most math problems.
Related Questions
math - 1.John deposited $40,000.oo in the bank and earned simple interest of 7% ...
math 11 - Calculate the amount of interest earned in 10 years on $1000 invested ...
Math - I hate word problems! Can anyone just change this Following word prob to...
algebra - an investor invested a total of 1,600 in 2 mutual funds.One fund ...
algebra - An investor invested a total of $2,600 in two mutual funds. One fund ...
algebra - An investor invested a total of $500 in two mutual funds. One fund ...
Math - A retired couple needs $12,000 per year in income to supplement their ...
Math - An investment advisor invested a total of $12,000, part at 2.5% annual ...
Math - O God I hate word problems! Is there any mechanical way to memorize word ...
math - A bank has loaned out $750,000, part of it at 5% per annum and the rest ...
For Further Reading