When a monoprotic weak acid is titrated with a strong base, the titration curve contains these many inflection points:

a.zero
b.one
c.two
d.three

Can you also explain why you choose your answer to this question...thanks

(2) In a weak acid-strong base or weak base-strong acid titration, the inflection point at which the slope is greatest also precedes the equivalence point, and vanishes under certain conditions. Earlier calculations are shown to have given incorrect information regarding the location and existence of this inflection point. The location of the inflection point at which the slope is smallest— the “point of maximum buffer capacity”—is shown to depend on the concentrations of the reagents employed.

To determine the number of inflection points in a titration curve, we need to consider the stoichiometry of the reaction between the weak acid and the strong base.

In the case of a monoprotic weak acid, it can donate or lose one proton (H+). When titrated with a strong base, such as NaOH, the acid reacts with the hydroxide ions (OH-) from the base to form water (H2O).

The reaction equation between the weak acid (HA) and strong base (NaOH) can be written as follows:

HA + NaOH -> H2O + NaA

Here, HA represents the weak acid and NaA represents the sodium salt of the acid.

Since the acid can donate only one proton, the stoichiometry of the reaction is 1:1. This means that for every mole of weak acid reacted, an equal mole of strong base reacts.

As a result, there will be only one inflection point in the titration curve. This inflection point corresponds to the point where the moles of strong base added are exactly equal to the moles of weak acid present.

Therefore, the correct answer is (b) one.