Posted by **Anonymous** on Thursday, March 25, 2010 at 10:39am.

A small 520-gram ball on the end of a thin, light rod is rotated in a horizontal circle of radius 1.5 m. Calculate the moment of inertia of the ball about the center of the circle. Then calculate the torque needed to keep the ball rotating at constant angular velocity if air resistance exerts a force of 0.015 N on the ball. Ignore the rod's moment of inertia and air resistance. I don't understand how to do this problem, please help with step-by-step.

## Answer this Question

## Related Questions

- physics - A 650g ball on the end of a light rod is rotated in a horizontal ...
- physics - A thin non-uniform rod of length L=2.00 m and mass M=9.00 kg is free ...
- Physics - So, "a uniform steel rod of length 1.20 meters and mass 6.40 kg has ...
- physics - A toy consisting of two balls, each m = 0.56 kg, at the ends of a l = ...
- Physics - An object is formed by attaching a uniform, thin rod with a mass of mr...
- physics - An object is formed by attaching a uniform, thin rod with a mass of mr...
- Physics - Two small charges with a mass of 1.0 g each are connected by 2.0-cm-...
- Physics - A nonuniform 2.0-kg rod is 2.0 m long. The rod is mounted to rotate ...
- 12th grade - A bicycle wheel has a radius of 0.330 m and a rim whose mass is 1....
- physics - A 0.55- ball, attached to the end of a horizontal cord, is rotated in ...