Post a New Question


posted by .

How many grams of iron(III) nitrate.9H2O could be formed from the reaction of 3.676 g of iron with excess HNO3?

Please can u explain? i try balance the question i couldnt.

  • chemistry -

    2Fe + 6HNO3 + 9H2O ==>2Fe(NO3)3.9H2O + 3H2

    1. Write and balance the equation as above.
    2. Convert 3.676 g Fe to moles. moles = grams/molar mass.
    3. Using the coefficients in the balanced equation, convert moles Fe to moles of the product.
    4. Now convert moles of the product to grams. g = moles x molar mass.
    Check my work. Post your work if get stuck.

  • chemistry -

    the answer is 11.17 or not

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question