Two small identical metal spheres, A and B, on insulated stands, are each given a charge of +2.4 10-6 coulomb. The distance between the spheres is 7 10-1 meter. Calculate the magnitude of the electrostatic force that the charge on sphere A exerts on the charge on sphere B.
_______N
Fe= 0.9 N
Fe = 9.0*10^-1 N
To calculate the magnitude of the electrostatic force between two charged spheres, we can use Coulomb's law.
Coulomb's law states that the magnitude of the electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
The formula for Coulomb's law is:
F = k * (q1 * q2) / r^2
where:
F is the magnitude of the electrostatic force,
k is the Coulomb's constant (k = 8.99 x 10^9 N m^2/C^2),
q1 and q2 are the charges on the two spheres, and
r is the distance between the two spheres.
In this case, both spheres A and B have a charge of +2.4 x 10^-6 C, and the distance between them is 7 x 10^-1 m.
Plugging in the values into the formula:
F = (8.99 x 10^9 N m^2/C^2) * (2.4 x 10^-6 C * 2.4 x 10^-6 C) / (7 x 10^-1 m)^2
Simplifying the expression:
F = (8.99 x 10^9 N m^2/C^2) * (5.76 x 10^-12 C^2) / (4.9 x 10^-2 m^2)
F = 4.16 x 10^-2 N
Therefore, the magnitude of the electrostatic force that the charge on sphere A exerts on the charge on sphere B is approximately 4.16 x 10^-2 Newtons (N).