Posted by **Anonymous ** on Wednesday, March 24, 2010 at 10:50pm.

if y=sec^(3)2x, then dy/dx=

my answer is 6 sec^3 2xtan 2x but im not sure if that is right. ?

Can someone show me if i did it correct.

- Math-Derivatives. -
**Reiny**, Thursday, March 25, 2010 at 12:03am
good job

- Math-Derivatives. -
**Anonymous **, Thursday, March 25, 2010 at 12:21am
Sorry to bother you, can you explain the steps to me, so I can see the work and check my work. I thought i had done it wrong, I started my work and then guessed.

- Math-Derivatives. -
**Reiny**, Thursday, March 25, 2010 at 12:25am
write it as

y = (sec (2x))^3

now use the chain rule ...

y' = 3(sec (2x)^2 (derivative of sec(2x))

= 3(sec (2x)^2(sec (2x))tan (2x))(2)

= 6(sec (2x))^3 tan (2x)

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