Posted by **Anonymous** on Wednesday, March 24, 2010 at 10:50pm.

if y=sec^(3)2x, then dy/dx=

my answer is 6 sec^3 2xtan 2x but im not sure if that is right. ?

Can someone show me if i did it correct.

- Math-Derivatives. -
**Reiny**, Thursday, March 25, 2010 at 12:03am
good job

- Math-Derivatives. -
**Anonymous**, Thursday, March 25, 2010 at 12:21am
Sorry to bother you, can you explain the steps to me, so I can see the work and check my work. I thought i had done it wrong, I started my work and then guessed.

- Math-Derivatives. -
**Reiny**, Thursday, March 25, 2010 at 12:25am
write it as

y = (sec (2x))^3

now use the chain rule ...

y' = 3(sec (2x)^2 (derivative of sec(2x))

= 3(sec (2x)^2(sec (2x))tan (2x))(2)

= 6(sec (2x))^3 tan (2x)

## Answer This Question

## Related Questions

- Integration - Intergrate ¡ì sec^3(x) dx could anybody please check this answer. ...
- calculus (check my work please) - Not sure if it is right, I have check with the...
- Calculus 12th grade (double check my work please) - 2- given the curve is ...
- math - Determine all the possible values of x where 0 deg is more than or equal ...
- Calculus AP - I'm doing trigonometric integrals i wanted to know im doing step ...
- Integration? - Use the derivatives of sinx and cosx to show that d/dx [tanx] = ...
- statistics - The time (sec) that it takes a librarian to locate an entry in a ...
- Calculus - not sure if my work is correct? - A 15ft ladder leans against a ...
- calculus - Did I do this problem right? Find the first and second derative-...
- calculus - i have to integrate using u substitution, but i am not sure if i did ...

More Related Questions