Find the voltage increase when 12 J of work is done to push a 0.0013 C charge into an electric field.
Well, according to my calculations, the voltage increase would be approximately 9230 volts. That's quite a shocking change! Just remember to stay positive and keep those electrons in line!
To find the voltage increase, we can use the formula:
V = W/q
Where:
V is the voltage increase,
W is the work done,
q is the charge.
Given:
W = 12 J
q = 0.0013 C
Substituting these values into the formula, we have:
V = 12 J / 0.0013 C
Calculating this gives:
V = 9230.769 volts
Therefore, the voltage increase when 12 J of work is done to push a 0.0013 C charge into an electric field is approximately 9230.769 volts.
To find the voltage increase, we can use the formula:
Voltage (V) = Work done (W) / Charge (Q)
We are given that the work done (W) is 12 J and the charge (Q) is 0.0013 C.
Substituting the values into the formula:
V = 12 J / 0.0013 C
To calculate this, divide 12 by 0.0013:
V = 9230.77 V (rounded to five decimal places)
Therefore, the voltage increase when 12 J of work is done to push a 0.0013 C charge into an electric field is approximately 9230.77 V.