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March 1, 2015

March 1, 2015

Posted by **roy** on Wednesday, March 24, 2010 at 5:55pm.

- algebra -
**Kathleen**, Wednesday, March 24, 2010 at 8:42pmX^-6 times X^5= X^-1 (add exponents

-6 + 5=-1

X to the negative 1 can be rewritten 1/X

so you have only postitve exponents.

Y^-12 divided by Y^5 = Y^-17 (subtract

exponents -12-5=-17)

So Y^-17=1/Y^17

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