Posted by pjl on .
A 4.90 g nugget of pure gold absorbed 255 J of heat. What was the final temperature of the gold if the initial temperature was 24.0°C? The specific heat of gold is 0.129 J/(g·°C).

chemistry 
DrBob222,
q = mass Au x specific heat Au x (TfinalTinitial)

chemistry 
Anonymous,
463.5342

chemistry 
NYC,
YOU CAN USE ALGEBRA!
energy absorbed=given grams x specific heat x (unknown final temperatureinitial temp)
SO:
255=4.90(.129)(x24)
255=0.6321(x24)
DIVIDE BOTH SIDES BY .6321
.6321(255)=(.6321(x24))/,6321
403.42 = x24
+24 +24

x=427.42