Posted by pjl on Wednesday, March 24, 2010 at 3:24pm.
A 4.90 g nugget of pure gold absorbed 255 J of heat. What was the final temperature of the gold if the initial temperature was 24.0°C? The specific heat of gold is 0.129 J/(g·°C).

chemistry  DrBob222, Wednesday, March 24, 2010 at 8:50pm
q = mass Au x specific heat Au x (TfinalTinitial)

chemistry  Anonymous, Monday, October 3, 2011 at 9:51am
463.5342

chemistry  NYC, Wednesday, March 19, 2014 at 9:28pm
YOU CAN USE ALGEBRA!
energy absorbed=given grams x specific heat x (unknown final temperatureinitial temp)
SO:
255=4.90(.129)(x24)
255=0.6321(x24)
DIVIDE BOTH SIDES BY .6321
.6321(255)=(.6321(x24))/,6321
403.42 = x24
+24 +24

x=427.42
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