Posted by **pjl** on Wednesday, March 24, 2010 at 3:24pm.

A 4.90 g nugget of pure gold absorbed 255 J of heat. What was the final temperature of the gold if the initial temperature was 24.0°C? The specific heat of gold is 0.129 J/(g·°C).

- chemistry -
**DrBob222**, Wednesday, March 24, 2010 at 8:50pm
q = mass Au x specific heat Au x (Tfinal-Tinitial)

- chemistry -
**Anonymous**, Monday, October 3, 2011 at 9:51am
463.5342

- chemistry -
**NYC**, Wednesday, March 19, 2014 at 9:28pm
YOU CAN USE ALGEBRA!

energy absorbed=given grams x specific heat x (unknown final temperature-initial temp)

SO:

255=4.90(.129)(x-24)

255=0.6321(x-24)

DIVIDE BOTH SIDES BY .6321

.6321(255)=(.6321(x-24))/,6321

403.42 = x-24

+24 +24

----------------

x=427.42

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