How do I find the dimensions of a piece of wrapping paper used to wrap the box? The dimensions are 15in, 9in, 4in. The SA equals 270.

I don't know to make it into an answer like 40 in. BY 10in

What does SA mean?

Surface area and I was wrong it ='s 462.0

To find the dimensions of the wrapping paper used to wrap the box, you need to understand how to calculate the surface area (SA) of a rectangular box. The surface area is the sum of the areas of all six sides.

For a rectangular box, the formula for surface area is:
SA = 2 * (length * width) + 2 * (width * height) + 2 * (length * height)

Given that the surface area (SA) is 270, and the dimensions of the box are 15in, 9in, and 4in respectively, we can substitute these values into the formula and solve for the missing dimension.

Let's label the dimensions as length (L), width (W), and height (H).

We have the equation:
270 = 2 * (L * W) + 2 * (W * H) + 2 * (L * H)

Substituting the given dimensions:
270 = 2 * (15 * W) + 2 * (W * 4) + 2 * (15 * 4)

Simplifying further:
270 = 30W + 8W + 120

Combining like terms:
270 = 38W + 120

Now, isolate W by subtracting 120 from both sides:
150 = 38W

Finally, divide both sides by 38:
W ≈ 3.95

So, the approximate width of the wrapping paper is 3.95 inches.

To find the other missing dimension, you can choose either the length or height and solve for it using the same equation. Let's use the length (L) in this example.

We have the equation:
270 = 2 * (L * 3.95) + 2 * (3.95 * 4) + 2 * (L * 4)

Simplifying further:
270 = 7.9L + 31.6 + 8L

Combining like terms:
270 = 15.9L + 31.6

Now, isolate L by subtracting 31.6 from both sides:
238.4 = 15.9L

Finally, divide both sides by 15.9:
L ≈ 14.99

So, the approximate length of the wrapping paper is 14.99 inches.

Therefore, the dimensions of the wrapping paper used to wrap the box are approximately 14.99 inches by 3.95 inches.