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December 19, 2014

December 19, 2014

Posted by **Edwin** on Wednesday, March 24, 2010 at 1:35pm.

- math -
**Reiny**, Wednesday, March 24, 2010 at 4:25pmtake the cross-product to (2,2,-1) and(-3,2,1)

which is (4,1,10)

So your line must have that directions

so the vector equation is

_

r = (1,1,2) + k(4,1,10)

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