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Posted by on Wednesday, March 24, 2010 at 9:37am.

A cyclist and a jogger start from a town at the same time and headed for a destination 24 mi away. The rate of the cyclist is twice the rate of the jogger. The cyclist arrives 3hrs ahead of the jogger. Whats the rate of the cyclist?

  • math - , Wednesday, March 24, 2010 at 11:29am

    C = 2J (rates)

    Distance = rate/time

    Therefore, time = rate/distance

    J/24 - C/24 = 3

    Use substitution to solve first for cyclist and then for jogger.

  • math - , Wednesday, March 24, 2010 at 11:48am

    is the answer 12

  • math (oops!) - , Friday, March 26, 2010 at 7:52pm

    Sorry, I goofed!

    Distance = rate * time

    Therefore, Time = Distance/rate

    24/J - 24/C = 3

    Substitute 2j for C.

    24/j - 24/2J = 3

    Multiply both sides by J.

    24 - 12 = 3J

    12 = 3j

    4 = J

    C = 2J = 2 * 4 = 8

    Sorry for the goof! This should help.

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