A cyclist and a jogger start from a town at the same time and headed for a destination 24 mi away. The rate of the cyclist is twice the rate of the jogger. The cyclist arrives 3hrs ahead of the jogger. Whats the rate of the cyclist?
math - PsyDAG, Wednesday, March 24, 2010 at 11:29am
C = 2J (rates)
Distance = rate/time
Therefore, time = rate/distance
J/24 - C/24 = 3
Use substitution to solve first for cyclist and then for jogger.
math - Chris, Wednesday, March 24, 2010 at 11:48am
is the answer 12
math (oops!) - PsyDAG, Friday, March 26, 2010 at 7:52pm
Sorry, I goofed!
Distance = rate * time
Therefore, Time = Distance/rate
24/J - 24/C = 3
Substitute 2j for C.
24/j - 24/2J = 3
Multiply both sides by J.
24 - 12 = 3J
12 = 3j
4 = J
C = 2J = 2 * 4 = 8
Sorry for the goof! This should help.