Posted by **Maryo** on Wednesday, March 24, 2010 at 1:36am.

The temperature in an electric oven is 160°C. The temperature at the outer surface in the kitchen is 50°C. The oven ( surface area = 1.6 m2) is insulated with material that has a thickness of 0.02 m and a thermal conductivity of 0.045 J/s.m.C°. (a) How much energy is used to operate the oven for six hours?(b) At the price of $0.1/kw-hr for electrical energy, what is the cost of operating the oven?

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**Maryo**, Wednesday, March 24, 2010 at 7:01am
Anyone Can answer this Please

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**drwls**, Wednesday, March 24, 2010 at 9:06am
Calculate the heat loss rate through the walls, using

P = (surface area)*k*(110C)/0.02 m

where k is the thermal conducticity

Convert watts (J/s) to kilowatts. Multiply the number of kW by 6h to get the number of kW-hr.

That is the energy required for steady state ooperation for 6 hours. There will be an additional amount required to heat up the oven - probably a few percent more, depending upon the specific heat.

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