Posted by Maryo on Wednesday, March 24, 2010 at 1:36am.
Anyone Can answer this Please
Calculate the heat loss rate through the walls, using
P = (surface area)*k*(110C)/0.02 m
where k is the thermal conducticity
Convert watts (J/s) to kilowatts. Multiply the number of kW by 6h to get the number of kW-hr.
That is the energy required for steady state ooperation for 6 hours. There will be an additional amount required to heat up the oven - probably a few percent more, depending upon the specific heat.
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