Posted by anon. on Wednesday, March 24, 2010 at 12:40am.
derivatives:
y=(x^3+1)^2, then dy/dx is:
i got 6x^2(x^3+1) first but im not sure.
Can i see the steps of how it is done right. I also got 2(3x^2+1), which one is right??
sorry for bugging.Thanks

math  Damon, Wednesday, March 24, 2010 at 8:21am
y=(x^3+1)^2, then dy/dx is:
i got 6x^2(x^3+1) first but im not sure.
Can i see the steps of how it is done right. I also got 2(3x^2+1), which one is right??

y' = 2(x^3+1)^1 dy/dx (x^3)
= 2 (x^3+1)(3)(x^2)
= 6 x^2 (x^3+1)
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