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March 28, 2015

March 28, 2015

Posted by **anon.** on Wednesday, March 24, 2010 at 12:40am.

y=(x^3+1)^2, then dy/dx is:

i got 6x^2(x^3+1) first but im not sure.

Can i see the steps of how it is done right. I also got 2(3x^2+1), which one is right??

sorry for bugging.Thanks

- math -
**Damon**, Wednesday, March 24, 2010 at 8:21amy=(x^3+1)^2, then dy/dx is:

i got 6x^2(x^3+1) first but im not sure.

Can i see the steps of how it is done right. I also got 2(3x^2+1), which one is right??

-----------------------------------

y' = 2(x^3+1)^1 dy/dx (x^3)

= 2 (x^3+1)(3)(x^2)

= 6 x^2 (x^3+1)

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