Posted by **sh** on Wednesday, March 24, 2010 at 12:24am.

Find an equation of the tangent line to the given curve at the given point

y=(1/cosx)-2cosx at((pi/3),1)

y'=0+2sinx

slope = √3

y=mx+b

1=(√3)(pi/3)+b

b=(3-√3pi)/3

3√3x-3y+3-√3pi=0

What did I do wrong? Thanks in advance.

- Calculus -
**sh**, Wednesday, March 24, 2010 at 1:20am
Got it.

## Answer This Question

## Related Questions

- Math - Find an equation of the line that bisects the obtuse angles formed by the...
- 8th grade algebra - Can you check my answers? 1. 3√20/√4 = 3√(...
- grade 11 math - I don't get how to do this. I'm so lost please help me. ...
- Algebra - How would i complete these problems? 1. (√6mn)^5 2. ^3√16x...
- maths - I will be thankfull to you if you help me to solve the below problem: 6...
- Algebra Work Check - 1. 5√6 * 1/6√216 5/6 * √1296 5/6 * √...
- Algebra 2 Answer Check - Simplify by rationalizing each denominator. 1. 2/√...
- Math - In this problem we consider drawing some straight lines which form a nice...
- algebra 1 - alright i have a few questions if its ok..? Simplify: 1. -2√(...
- Algebra 2 - Can someone help me with this radical expression please? The problem...

More Related Questions