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College Chemistry

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Calculate the ratio of NaF to HF required to create a buffer with pH=3.95.

Also, can you please explain in a nutshell the whole concept of buffers?

Thanks!

  • College Chemistry - ,

    Never mind, I figured it out.

  • College Chemistry - ,

    what was the anwer?

  • College Chemistry - ,

    pH=pKa + log(base/acid)
    3.95=3.465 + log(base/acid)
    .494=log(base/acid)
    10^.494
    3.1

  • College Chemistry - ,

    thanks!!

  • College Chemistry - ,

    wait what? that's not right the -log(.494) = 2.02

  • College Chemistry - ,

    john the answer is right 3.1; u have to key on ur calc 2nd key then log key then the (^)key :) to get that answer.

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