Magnet A has twice the magnetic field strength of magnet B and at a certain distance pulls on magnet B with a force of 75 N. With how much force, then, does magnet B pull on magnet A?

Dont forces always occur in equal an opposite pairs? What does Newtons third law mean?

Apply the same logic to
earth and you. One has a million times the gravitational field strength as the other. On the surface, you weigh 165lbs? How much are you pulling on the Earth: ANS 165lbs.

75N

To determine the force with which magnet B pulls on magnet A, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

Since magnet A has twice the magnetic field strength of magnet B, the force exerted by magnet B on magnet A would be equal in magnitude but opposite in direction to the force exerted by magnet A on magnet B.

Therefore, the force with which magnet B pulls on magnet A is also 75 N.

To determine the force with which magnet B pulls on magnet A, we need to use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. In other words, the force exerted by magnet B on magnet A will be the same magnitude but in the opposite direction as the force exerted by magnet A on magnet B.

Given that magnet A has twice the magnetic field strength of magnet B, we can assume that the force exerted by magnet B on magnet A is half of the force exerted by magnet A on magnet B. So, if the force exerted by magnet A on magnet B is 75 N, the force exerted by magnet B on magnet A would be:

Force = (1/2) * 75 N = 37.5 N

Therefore, magnet B pulls on magnet A with a force of 37.5 N.