College Chemistry
posted by Kyle on .
Amphetamine (C9H13N) is a weak base with a pKb of 4.2.
Calculate the pH of a solution containing an amphetamine concentration of 215 mg/L.
I calculated the molarity as 1.58*10^3 and the Ka as 1.58*10^10. I did ICE and i got the pH as 6.3, but it was wrong. Do you know what I did wrong?

I think you treated amphetamine as a salt. Its a base. pKa of 4.2 makes Kb = 6.3 x 10^5. If we represent amphetamine as RN, then
RN + HOH ==> RNH^+ + OH^
Kb = (RNH^+)(OH^)/(RN)
6.3 x 10^5 = (x)(x)/1/59 x 10^3
solve for x which is (OH^), convert to pOH, then to pH. I get something like 10.5 but that's a quickie. Check it out.