Homework Help: Math(Correction)

Posted by Mark on Tuesday, March 23, 2010 at 6:12pm.

Use the given function values and trigonometric identities (including the relationship between a trigonometric function and its cofunction of a complementary angle) to find the indicated trigonometric functions.

sec Q = 5

tan Q = 2sqrt6

a) cos Q

b) cotQ

c) cot(90 degrees - Q)

d) sin Q

Math(Correction) - Reiny, Tuesday, March 23, 2010 at 6:21pm
Ok, finally , now it makes sense
And now it is easy.

given: secQ = 5, then cosQ = 1/5

So we have a right angles triangle, where the hypotenuse is 5, the side adjacent to angle Q is 1, and the opposite to angle Q is 2√6

Notice that the second function, tanQ = 2√6 was not necessary, since we can see that from our triangle.

a) cosQ = 1/5
b) cotQ = 1/tanQ = 1/(2√6)
c) cot(90 - Q) = tan Q = 2√6
d) sinQ = 2√6/5
Math(Correction) - DIKSHA, Saturday, July 7, 2012 at 7:32am
SIN(90-Q)/COSEC(90-Q)=COS(90-Q)/COSEC(90-Q)
Math(Correction) - DIKSHA, Saturday, July 7, 2012 at 7:33am
SIN(90-Q)/COSEC(90-Q)+COS(90-Q)/COSEC(90-Q)=1
Math(Correction) - DIKSHA, Saturday, July 7, 2012 at 7:34am
SIN(90-Q)/COSEC(90-Q)+COS(90-Q)/COSEC(90-Q)=1

Answer this Question

Related Questions

Math(Correction) - Use the given function values and trigonometric identities (...
Math - Use the given function values and trigonometric identities (including ...
Math(Correction) - Use the given function values and trigonometric identities (...
Trigonometry - I don't understand how I'm supposed set the problem up or...
Trig. - I really need help so please help. write the first trigonometric ...
Math - Use the sum or difference identities to find the exact value of each ...
Trigonometric Identities - Which of the following are trigonometric identities, ...
Trig - How do you express these problems as single trigonometric function values...
Trig - How do you express these problems as single trigonometric function values...
trig - use sum or difference identities to find the exact value of the ...

For Further Reading

First Name:
School Subject:
Answer: