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January 26, 2015

January 26, 2015

Posted by **Matt O.** on Tuesday, March 23, 2010 at 7:11am.

- Math -
**Reiny**, Tuesday, March 23, 2010 at 8:19amAre you the same James who posted several versions of this yesterday?

http://www.jiskha.com/display.cgi?id=1269297854

If so, it is an improvement, but still not too clear.

I think that (x^2+5x)+(xy+5y) probably should be the entire denominator of the first fraction, you didn't type it that way, so I will read the question this way ....

(y-5)/[(x^2+5x)+(xy+5y)] + 1/(x+y) - 2/(x+5)

= (y-5)/[x(x+5)+y(x+5)] + 1/(x+y) - 2/(x+5)

= (y-5)/[(x+5)(x+y)] + 1/(x+y) - 2/(x+5)

now we have (x+5)x+y) as a common denominator, so

=(y-5)/[(x+5)(x+y)] + (x+5)/[(x+5)(x+y)] - 2(x+y)/[(x+5)(x+y)]

= (y-5 + x + 5 - 2x - 2y)/(x+5)(x+y)]

= (-x - y)/[(x+5)(x+y)]

= -(x+y)/[(x+5)(x+y)]

= -1/(x+5)

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