Posted by L** on Tuesday, March 23, 2010 at 1:03am.
A 5.0 gram coin is placed 5.0 cm from the axis of a rotating turntable of variable speed. When the speed of the turntable is slowly increased, the coin remains fixed on the turntable until a rate of 36 RPM is reached and the coin slides off.
A.) What is the coefficient of static friction between the coin and the turntable?
B.)What is the acceleration at that moment?
C.) What is the centripetal force then?

College Physics  drwls, Tuesday, March 23, 2010 at 5:15am
At 36 rpm, the angular velocity is
w = 36*(2 pi)/60 = 6pi/5 = 3.770 radians/sec.
A) mus*M g = M r w^2
mus = rw^2/g = (0.05)(3.77)^2/9.81 = 0.072
B)Before it starts slipping, the acceleration is
rw^2 = (0.05)(3.77)^2 = 0.71 m/s^2
After it starts slipping, it depends upon the kinetic coefficient of friction. More information is needed to get that.
c)centripetal force = M r w^2
Answer This Question
Related Questions
 Physics  A coin is placed 17.0 from the axis of a rotating turntable of ...
 Physics  A coin is placed 11.0 cm from the axis of a rotating turntable of ...
 Physicscircular force  A coin is placed 11.0 cm from the axis of a rotating ...
 Physics: Help  A coin is placed 12.5 cm from the axis of a rotating turntable ...
 physics  A coin is placed 14.0 cm from the axis of a rotating turntable of ...
 phisycis  A coin is placed 14.0 cm from the axis of a rotating turntable of ...
 physics  A coin is placed 20 cm from the axis of a rotating turntable of ...
 Physics  (b)A coin is placed 20 cm from the axis of a rotating turntable of ...
 physics  A coin is placced 12.0 cm from the axis of a roatating turntable of ...
 Physics  A coin is placced 12.0 cm from the axis of a roatating turntable of ...
More Related Questions