posted by Ralph on .
The combustion reaction of acetylene gas is represented by this equation:
2 C2H2(g) + 5 O2(g) ==> 4 CO2(g) + 2 H2O(g)
How many grams of CO2 and grams of H2O are produced when 52.0g C2H2 burns in oxygen?
Convert 52.0 g C2H2 to moles. moles = grams/molar mass.
Using the coefficients in the balanced equation, convert moles acetylene to moles CO2 and do the same thing for moles H2O.
Now convert those moles to grams. g = moles x molar mass.
When 1 mole of tin IV oxide is heated with 2 moles of hydrogen gas, 1 mole of tin metal and 2 moles of water vapor are generated.
SnO¿ + 2H¿d Sn + 2H¿O
How many moles of tin metal will be produced when 0.74 moles of tin IV oxide is heated?
The answer would be 0.74 I just answered this question and got the go