Write the 12 mole ratios that can be derived from the equations for the combustion of isopropyl alcohol.

2 C3H7OH(l) + 9 O2(g) ==> 6 CO2(g) + 8 H2O (g)

To determine the mole ratios, we compare the coefficients of the reactants and products in the balanced equation for the combustion of isopropyl alcohol. The coefficients represent the number of moles of each substance involved in the reaction.

The balanced equation is:

2 C3H7OH(l) + 9 O2(g) ==> 6 CO2(g) + 8 H2O(g)

From this equation, we can derive the following 12 mole ratios:

1. Moles of isopropyl alcohol (C3H7OH) to moles of carbon dioxide (CO2):
2 mol C3H7OH : 6 mol CO2

2. Moles of isopropyl alcohol (C3H7OH) to moles of water (H2O):
2 mol C3H7OH : 8 mol H2O

3. Moles of oxygen (O2) to moles of carbon dioxide (CO2):
9 mol O2 : 6 mol CO2

4. Moles of oxygen (O2) to moles of water (H2O):
9 mol O2 : 8 mol H2O

5. Moles of carbon dioxide (CO2) to moles of isopropyl alcohol (C3H7OH):
6 mol CO2 : 2 mol C3H7OH

6. Moles of carbon dioxide (CO2) to moles of oxygen (O2):
6 mol CO2 : 9 mol O2

7. Moles of water (H2O) to moles of isopropyl alcohol (C3H7OH):
8 mol H2O : 2 mol C3H7OH

8. Moles of water (H2O) to moles of oxygen (O2):
8 mol H2O : 9 mol O2

9. Moles of carbon dioxide (CO2) to moles of water (H2O):
6 mol CO2 : 8 mol H2O

10. Moles of carbon dioxide (CO2) to moles of carbon dioxide (CO2):
6 mol CO2 : 6 mol CO2

11. Moles of water (H2O) to moles of water (H2O):
8 mol H2O : 8 mol H2O

12. Moles of isopropyl alcohol (C3H7OH) to moles of isopropyl alcohol (C3H7OH):
2 mol C3H7OH : 2 mol C3H7OH

These ratios allow us to calculate the amount of each substance involved in the combustion of isopropyl alcohol based on the given amount of any other substance.

To derive mole ratios from the given balanced equation for the combustion of isopropyl alcohol, we can compare the coefficients of the reactant (isopropyl alcohol) and the products (carbon dioxide and water). Here are the 12 mole ratios that can be derived:

1. 2 moles of C3H7OH react with 6 moles of CO2
2. 2 moles of C3H7OH react with 8 moles of H2O
3. 9 moles of O2 react with 6 moles of CO2
4. 9 moles of O2 react with 8 moles of H2O
5. 2 moles of C3H7OH react with 9 moles of O2
6. 6 moles of CO2 are produced from 2 moles of C3H7OH
7. 6 moles of CO2 are produced from 9 moles of O2
8. 8 moles of H2O are produced from 2 moles of C3H7OH
9. 8 moles of H2O are produced from 9 moles of O2
10. 6 moles of CO2 are produced from 8 moles of H2O
11. 9 moles of O2 react with 6 moles of CO2
12. 8 moles of H2O are produced from 6 moles of CO2

These mole ratios can be used to calculate the quantities of reactants consumed or products produced in a given combustion reaction involving isopropyl alcohol.

I'll do one but not 12. Actually, there are six and the reversal of the six to make twelve.

2 moles C3H7OH/9 moles O2 and the reverse (perhaps I should have said reciprocal) of that is
9 moles O2/2 moles C3H7OH.