Posted by **Anonymous** on Monday, March 22, 2010 at 2:14pm.

Suppose sin theda= – 3/5 and theda is a Quadrant III angle.

Find the exact value of sin 2 theda and cos 2 theda.

- trig -
**tradejack**, Monday, March 22, 2010 at 2:39pm
It is theta not theda. Quadrant III= a reflex angle greater than 180 degrees and yet less than or = to 270 degrees.

- trig -
**tradejack**, Monday, March 22, 2010 at 2:39pm
as measured counterclockwise from the origin (0,0).

- trig -
**Reiny**, Monday, March 22, 2010 at 3:46pm
since sinØ = -3/5, in the third quad cosØ = -4/5

sin 2Ø = 2sinØcosØ = 2(-3/5)(-4/5) = 24/25

cos 2Ø = cos^2 Ø - sin^2 Ø = 16/25 - 9/25 = 7/25

## Answer this Question

## Related Questions

- Math - Find the exact value of cot theda if theda is in standard position and (-...
- math - How to solve for delta using trig functions? i.e. cosine sine tangent ...
- Physics - A beam of light is incident on the surface of clear ice at 60 degrees ...
- Physics - A ray of light stikes a flat 2 cm thick block of ice (n=1.5) at an ...
- MATH - solve for theda given 0<theda<2pi cos theta= - (sqrt 3)/ 2
- Physics - A force F is exerted by a broom handle on the head of the broom, which...
- Physics - n=1.331 for red light in water and n=1.34 for blue light in water. If ...
- trig - from the intervals 0 less than or equal to theda less than 2 pie, what is...
- Physics - The incident ray comes at 30 degrees to normal at the air/glass ...
- physics - Two blocks each with weight w are held in place on a frictionless ...