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October 10, 2015
Posted by **karen** on Monday, March 22, 2010 at 11:00am.

- math -
**Reiny**, Monday, March 22, 2010 at 11:02amsee the bottom part of my reply to

http://www.jiskha.com/display.cgi?id=1269266887

- math -
**Reiny**, Monday, March 22, 2010 at 11:13amFor your equation

r - 3cosŲ = 5sinŲ

√(x^2 + y^2) - 3x/r = 5y/r

√(x^2 + y^2) = 5y/r + 3x/r

√(x^2 + y^2) = (5y + 3x)/r

√(x^2 + y^2) = (5y + 3x)/√(x^2 + y^2)

cross multiply

x^2 + y^2 = 5y + 3x

which looks like the equation of a circle to me