Posted by Jenny on .
A solar panel (an assemblage of solar cells) measures 58 cm x 53 cm. When facing the Sun, this panel generates 2.7 A at 14 V. Sunlight delivers an energy of 1.0×10^3 W/m^2 to an area facing it. What is the efficiency of this panel, that is, what fraction of the energy in sunlight is converted into electric energy?
Power out = V I = 2.7*14 = 37.8 W
Solar Power in = (Area)*(Irradiance)
= 0.58 * 0.53 * 1000 = 307.4 W
Efficiency = (Power out)/(Power in)