Tuesday
September 16, 2014

Homework Help: Physics

Posted by Selma on Monday, March 22, 2010 at 12:59am.

A voltmeter of internal resistance of 5000 Ω is connected across the poles of a battery of internal resistance 0.20 Ω. The voltmeter reads 1.4993 volts. What is the actual zero-current emf of the battery?

Would this formula be I = V/(r+R) = 1.4993/(5000+0.20)?

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