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September 22, 2014

September 22, 2014

Posted by **sh** on Sunday, March 21, 2010 at 11:02pm.

y=(1+cos²x)^6

y'=6(1+cos²x)^5

How do you derive inside the brackets? The answer says -sin2x, but wouldn't it be -2sinx, using the chain rule.

- Calculus -
**Reiny**, Sunday, March 21, 2010 at 11:06pmYou still have to differentiate the "inside"

d(1+cos^2x) = 2cosx(-sinx)

= -2sinxcox

= -sin 2x, one of the identities

so

y'=6(1+cos²x)^5(-sin2x)

= y'= -6(1+cos²x)^5(sin2x)

- Calculus -
**sh**, Sunday, March 21, 2010 at 11:30pmOh, I see it now, thanks!

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