Posted by sh on Sunday, March 21, 2010 at 11:02pm.
You still have to differentiate the "inside"
d(1+cos^2x) = 2cosx(-sinx)
= -2sinxcox
= -sin 2x, one of the identities
so
y'=6(1+cos²x)^5(-sin2x)
= y'= -6(1+cos²x)^5(sin2x)
Oh, I see it now, thanks!
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