Posted by sh on Sunday, March 21, 2010 at 11:02pm.
Find the derivative of y with respect to x:
How do you derive inside the brackets? The answer says -sin2x, but wouldn't it be -2sinx, using the chain rule.
Calculus - Reiny, Sunday, March 21, 2010 at 11:06pm
You still have to differentiate the "inside"
d(1+cos^2x) = 2cosx(-sinx)
= -sin 2x, one of the identities
= y'= -6(1+cos²x)^5(sin2x)
Calculus - sh, Sunday, March 21, 2010 at 11:30pm
Oh, I see it now, thanks!
Answer This Question
More Related Questions
- Calculus - Solve identity, (1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting ...
- Trig--check answer - Solve the equation of the interval (0, 2pi) cosx=sinx I ...
- trigonometry - Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+...
- trig - sinx = 4/5 and x terminates in Quadrant II Find sin2x and cos2x How to ...
- Calculus - How do you find the derivative of f(x)=sin2x/cos2x
- Calculus grade 12 - solve for (<_ = less than or equal to / pie = pie sign...
- Maths - Prove that sin2x+cos2x-1/sin2x+cos2x+1=tanx
- maths - prove that 1+sin2x-cos2x / sin2x+cos2x = tanx
- Calculus - In the interval (0 is less than or equal to x which is less than or ...
- trig - write sin4xcos2 as the sum or difference of two functions. answers: 1/2(...