Posted by Kiki on Sunday, March 21, 2010 at 10:38pm.
You are right about C. A can use the C2H3O2 ion to form HC2H3O2 (acetic acid) and now you have the weak acid and its salt.
B is RbOH and HBr. RbOH is a strong base (think NaOH). HBr is a strong acid (think HCl). That's the main reason B can't be a buffer. D is a buffer because H2PO4^- is the conjugate base for H3PO4.
E is an acid/base reaction. KOH + HF ==> KF + H2O. But if you have the proportions right you can have some HF left over (not neutralized so you have a weak acid and the salt (KF) and that is a buffer.
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