Posted by **drwales** on Sunday, March 21, 2010 at 10:34pm.

A capacitor of capacitance C= 10mF, is charged using a battery of potential V, through a resistor of resistance R = 250 ohms.

the charge of the capacitor is given by

Q(t)=CV[1− e ^ (−t/RC)]

Find an expression for the current passing through the resistor as a function of time, and make a graph clearly indicating the initial values. how long will it take for the current passing through the resistor to drop to 37% of its max value?

## Answer this Question

## Related Questions

- Physics - Two circular metal disc each of 3.00 cm diamter are 1.5 mm apart make ...
- Physics - A q = +3.00 mC test charge is placed inside a constant uniform ...
- Physics - An RC-circuit has a time constant of 6x10-3 seconds. The capacitor ...
- physics - Having trouble with this one: A capacitor having a capacitance of 10uF...
- Physics - How long will it take the voltage across the capacitor in an RC ...
- Physic II - Suppose a capacitor of C=2.0 uF with no excess charge on it is ...
- SCience - An RC-circuit has a time constant of 6x10-3 seconds. The capacitor ...
- physics - A capacitor that powers the flash in a camera is charged using 6.0 V ...
- physics - The capacitor that powers the flash in a camera is charged using ^.0V ...
- Physics - In a portable deﬁbrillator, energy is stored in a capacitor ...

More Related Questions