posted by John on .
100-g sample of substance is heated to 100˚C and placed into calorimeter cup containing 150 g of water at 25˚C. The sample raises the temperature of water to 32.1. What is the specific heat of the substance?
The amount of heat transfered to the water is 150*7.1*1.0 = 1065 calories.
Removing that amount of heat from 100 g of the substance caused its temperature to drop 67.9 C. The specific heat can be calculated from that information.
C = Q/(M*deltaT) = 0.157 Cal/gm C
= 0.657 J/g K