Posted by Paula on Sunday, March 21, 2010 at 9:45pm.
There are 10 women and 8 men in a club. How many different committees of 6 people can be selected from the group if equal numbers of men and women are to be on the committee?
I think it would be 2, because half of 6 is 3, so 3 are men and 3 are women.
2 committees of 3 each would work, but 3 committees of 3 each would not since there are only 8 men. I can't figure out to put it into an equation to get 2 as the answer. (This sounds like something Edith Bunker would say, if you know who she is.)
Thanks for all your help.

math word problem  Reiny, Sunday, March 21, 2010 at 11:31pm
This is a combination question
You want to choose 3 women from the 10 and 3 men from the 8
number of committees = C(10,3)*C(8,3)
= 120*56 = 6720

math word problem  Paula, Friday, March 26, 2010 at 12:22am
I can't figure out where you got the 120 and 56.
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