Posted by **Paula** on Sunday, March 21, 2010 at 9:45pm.

There are 10 women and 8 men in a club. How many different committees of 6 people can be selected from the group if equal numbers of men and women are to be on the committee?

I think it would be 2, because half of 6 is 3, so 3 are men and 3 are women.

2 committees of 3 each would work, but 3 committees of 3 each would not since there are only 8 men. I can't figure out to put it into an equation to get 2 as the answer. (This sounds like something Edith Bunker would say, if you know who she is.)

Thanks for all your help.

- math word problem -
**Reiny**, Sunday, March 21, 2010 at 11:31pm
This is a combination question

You want to choose 3 women from the 10 and 3 men from the 8

number of committees = C(10,3)*C(8,3)

= 120*56 = 6720

- math word problem -
**Paula**, Friday, March 26, 2010 at 12:22am
I can't figure out where you got the 120 and 56.

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