Posted by **michelle** on Sunday, March 21, 2010 at 8:43pm.

How would u solve

D\d+2 - 2\2-d = d+6\ d^2-4

I got to

D(d-2)(2-d) -2 (d+2)(d-2)=2d-d^2+12-6d

How would you solve? Im confused

- algebra -
**Reiny**, Sunday, March 21, 2010 at 8:51pm
Did you not notice that the denominator of the right side is (d-2)(d+2) ?

I will also assume that D is really d, or else you have 2 unknowns.

so let's rewrite ...

d/(d+2) - 2/(2-d) = (d+6)/[(d+2)d-2)]

d/(d+2) **+ 2/(d-2)** = (d+6)/[(d+2)d-2)]

now multiply each term by (d+2)(d-2)

d(d-2) + 2(d+2) = d+6

d^2 - 2d + 2d + 4 = d + 6

d^2 - d - 2 = 0

(d-2)(d+1) = 0

d = 2 or d = -1

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