Homework Help: ocean county college

Posted by adina on Sunday, March 21, 2010 at 8:10pm.

A 150 g sample of metal at 55.0 C raises the temperature of 150 g of water from 23.0 C to 35.0 C. Determine the specific heat of the metal in J/g C.
Hint: #1 First find heat absorbed by water using formula q = mass x specific heat x change in temp (of water).
#2 Use this value to solve for specific heat of the metal. Remember final temperatures is the same for both metal and water.
Specific heat of water is 4.184 J/g C

Chemistry - Ms. Sue, Sunday, March 21, 2010 at 8:11pm
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ocean county college - DrBob222, Sunday, March 21, 2010 at 9:16pm
heat lost by the metal + heat gained by the water = 0.

mass metal x specific heat metal x [(Tfinal-Tinital)] + [mass water x specific heat water x (Tfinal-Tinital)] = 0

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