Determine the pH of each of the following solution.
a solution that is 5.8×10^−2 M in HClO4 and 2.6×10^−2 M in HCl
pH = -log(concentration)
pH of HClO4= -log(5.8x 10^-2 M)
use a calculator and figure it out
do the same for the second.
HCl is done the same way as HClO4.
To determine the pH of a solution, you need to know the concentration of the hydrogen ion (H+). In this case, we have two separate solutions: one is 5.8×10^−2 M in HClO4, and the other is 2.6×10^−2 M in HCl.
First, let's calculate the concentration of H+ in each solution.
HClO4 is a strong acid, meaning it dissociates completely in water, producing H+ ions. Therefore, the concentration of H+ in the HClO4 solution is equal to the concentration of HClO4 itself.
[H+] in the HClO4 solution = 5.8×10^−2 M
HCl is also a strong acid, so its concentration of H+ is equal to its concentration:
[H+] in the HCl solution = 2.6×10^−2 M
To find the pH of each solution, we need to take the negative logarithm (base 10) of the hydrogen ion concentration.
pH = -log[H+]
For the HClO4 solution:
pH = -log(5.8×10^−2)
= -log(5.8) - log(10^−2)
= -1.76
For the HCl solution:
pH = -log(2.6×10^−2)
= -log(2.6) - log(10^−2)
= -1.59
Therefore, the pH of the solution that is 5.8×10^−2 M in HClO4 is approximately 1.76, and the pH of the solution that is 2.6×10^−2 M in HCl is approximately 1.59.