determine the number of solutions using determinants
3x-y=-6
2x=3y+2
I get:
3 -1
2 -3
D = -9-(-2)=-7
and
3 -6
2 2
D = 6-(-12)=18
solution set is (-7,18)
when I plug them in to check, they don't come out right
that's not how you do it
your value of D = -7 is correct, but that becomes the denominator of both the x and the y
now replace the x column with the constants
-6 -1
2 -3
det of that = 18- (-2) = 20
so x = 20/-7
now replace the y column with the constants
3 -6
2 2
det = 6-(-12) = 18
y = 18/-7
I checked my answers by subbing back, they work