Posted by Jennifer on .
let f(x)=sqrt of 121x^2
a. graph the function
b. state the domain and range of f(x)

math 
Damon,
y=sqrt[121x^2]
a. graph the function
b. state the domain and range of f(x)
when x = +11, y = 0
when x = 11, y = 0
when x = 0, y = 11 never gets bigger
If x > 11 , y is imaginary
so parabola is upside down with vertex at (0,11) and zeros at +and  11
It never goes below the y axis
It never goes above y = 11
That defines the range and
x is from 11 to + 11 defining the domain 
math 
Jennifer,
so the domain is [11,11)