Posted by **Jennifer** on Sunday, March 21, 2010 at 7:00pm.

let f(x)=sqrt of 121-x^2

a. graph the function

b. state the domain and range of f(x)

- math -
**Damon**, Sunday, March 21, 2010 at 7:18pm
y=sqrt[121-x^2]

a. graph the function

b. state the domain and range of f(x)

when x = +11, y = 0

when x = -11, y = 0

when x = 0, y = 11 never gets bigger

If |x| > 11 , y is imaginary

so parabola is upside down with vertex at (0,11) and zeros at +and - 11

It never goes below the y axis

It never goes above y = 11

That defines the range and

x is from -11 to + 11 defining the domain

- math -
**Jennifer**, Sunday, March 21, 2010 at 7:28pm
so the domain is [-11,11)

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