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August 1, 2014

August 1, 2014

Posted by **Chad** on Sunday, March 21, 2010 at 5:52pm.

(x^2-y^2)/(x^2-2xy+y^2) divided by (3x+3y)/(7x-21)

Could someone please show me how to do this so I can do the rest of my homework? I don't understand this at all. Thank You

- Math -
**Damon**, Sunday, March 21, 2010 at 6:02pm(x^2-y^2) = (x+y)(x-y)

x^2-2xy+y^2 = (x-y)(x-y)

so when you divide the first by the second you get

(x+y)/x-y)

Now work on the bottom

(3x+3y) = 3(x+y)

(7x-21)= 7(x-3)

Now turn that upside down and multiply by the numerator

7(x-3) /3(x+y) * (x+y)/(x-y)

(7)(x-3)/3(x-y)

- Math -
**Anonymous**, Monday, February 18, 2013 at 7:32pm-1(y+6)+3(y+1)+7y

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