Solve by the elimination method
2r-5s=1
5r+2s=46
The solution is _______, or there are infinitely many solutions, or there is no solution
4r - 10s = 2 (multiplied by 2)
25r +10s = 230 (multiplied by 5)
Add the two equations.
29r = 232
r = 8
which of these is an easy way to solve the following system using the sustitution method:-3x+4y=11 and x+6y=0
To solve the system of equations using the elimination method, we need to eliminate one variable by adding or subtracting the equations.
Let's eliminate the variable "s" by multiplying the first equation by 2 and the second equation by 5:
Equation 1: 2r - 5s = 1
Equation 2: 5r + 2s = 46
Multiply Equation 1 by 2:
4r - 10s = 2
Multiply Equation 2 by 5:
25r + 10s = 230
Now, let's add the two equations together to eliminate the "s" variable:
(4r - 10s) + (25r + 10s) = 2 + 230
4r + 25r - 10s + 10s = 232
29r = 232
Divide both sides of the equation by 29:
r = 8
Now that we have solved for "r," we can substitute this value back into one of the original equations to solve for "s."
Using Equation 1:
2r - 5s = 1
2(8) - 5s = 1
16 - 5s = 1
-5s = 1 - 16
-5s = -15
s = (-15) / (-5)
s = 3
Therefore, the solution to the system of equations is r = 8 and s = 3.
Hence, the solution is r = 8, s = 3.