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November 27, 2014

November 27, 2014

Posted by **sh** on Sunday, March 21, 2010 at 2:38pm.

y=3sin^4(2-x)^-1

y=[3sin(2-x)^-1]^4

y'=4[3sin(2-x)^-1]^3 (-3cos(2-x)^-1)(-1) -(2-x)^-2

y'=[12cos(2-x)^-1][3sin^3(2-x)^-1][2-x]^2

but the answer does not have a 3 in front of sin. What happened to the 3?

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