I am less than 500. I am divisible by 11 and 5. I have three digits. The sum of my digits is 14
275
To be divisible by both 11 and 5, the number must be a multiple of 55
those are: 55, 110, 165, 220, 275, ..
ahh, 275 has its digits add up to 14
For questions in the area of "pure" math such as this question, for me the method of obtaining the answer was more important than the answer itself.
To find the answer to this question, we need to consider the given information and narrow down the possibilities.
First, we know that the number is less than 500 and has three digits. This means it could be any number from 100 to 499.
Next, we know that the number is divisible by both 11 and 5. To determine if a number is divisible by 11, we can examine the difference between the sum of its digits in even positions and the sum of its digits in odd positions. If this difference is 0 or a multiple of 11, then the number is divisible by 11.
In this case, the sum of the digits is given as 14. So, let's consider some possible combinations to find a valid number:
- If the hundreds digit is 1, possible combinations for the tens and units digits could be 3 and 10 or 8 and 6. However, neither of these combinations results in a sum of 14 for the digits.
- If the hundreds digit is 2, possible combinations for the tens and units digits could be 5 and 9 or 1 and 3. The combination 5 and 9 sums up to 14. Therefore, the number could be 259.
Thus, the number that satisfies all the given conditions is 259.