How do i write the equation betwen ethanoic acid CH3COOH and urea (NH2)2CO?

I think they form carbondioxide and an ammonium salt, but how do i write the actual equation?

To write the complete balanced equation between ethanoic acid (CH3COOH) and urea ((NH2)2CO), we need to consider the reaction conditions and the products formed.

When ethanoic acid reacts with urea, it undergoes a condensation reaction known as the Hofmann degradation. Under basic conditions, the products of this reaction are carbon dioxide (CO2) and ammonium acetate (NH4CH3COO).

Here is the step-by-step equation:

Step 1: Write the balanced chemical equation for the conversion of ethanoic acid into acetate ions:
CH3COOH + OH- → CH3COO- + H2O

Step 2: Write the balanced chemical equation for the conversion of urea into urea hydroxide:
(NH2)2CO + H2O → NH2CONH2 + OH-

Step 3: Combine the acetate ion (CH3COO-) and the urea hydroxide (NH2CONH2) to form ammonium acetate:
CH3COO- + NH2CONH2 → NH4CH3COO

Step 4: Write the balanced chemical equation for the conversion of water into carbon dioxide and ammonium hydroxide, which then further reacts to produce ammonium acetate:
NH4OH → NH3 + H2O
2NH3 + CO2 → (NH2)2CO + H2O

Combining these reactions, the complete balanced equation is:

CH3COOH + (NH2)2CO + OH- → NH4CH3COO + CO2 + NH3 + H2O

Remember that balancing coefficients may need to be adjusted to ensure the equation is balanced.

To write the balanced chemical equation for the reaction between ethanoic acid (CH3COOH) and urea ((NH2)2CO), you need to first identify the products that are formed during the reaction.

Ethanoic acid (CH3COOH) is a weak acid, while urea ((NH2)2CO) is an amide compound that contains a carbonyl group. When these two compounds react, they can form an ammonium salt, carbon dioxide (CO2), and water (H2O).

First, let's write the chemical formulas of the products:
1. Ammonium salt: (NH4)2COO
2. Carbon dioxide: CO2
3. Water: H2O

Now, let's write the balanced equation by considering the conservation of atoms. Start by examining the carbon atoms, then the nitrogen atoms, and finally the hydrogen and oxygen atoms.

CH3COOH + (NH2)2CO → (NH4)2COO + CO2 + H2O

To balance the equation, follow these steps:
1. Balance the carbon atoms: There is 1 carbon atom on the left side and 1 carbon atom on the right side, so they are already balanced.
2. Balance the nitrogen atoms: There are 2 nitrogen atoms on the left side and 2 nitrogen atoms on the right side, so they are already balanced.
3. Balance the hydrogen atoms: There are 6 hydrogen atoms on the left side (3 from CH3COOH and 3 from (NH2)2CO), and 8 hydrogen atoms on the right side (4 from (NH4)2COO and 4 from H2O). Add a coefficient of 4 in front of H2O to balance the hydrogen atoms.
CH3COOH + (NH2)2CO → (NH4)2COO + CO2 + 4H2O

4. Balance the oxygen atoms: There are 2 oxygen atoms on the left side and 10 oxygen atoms on the right side (2 from (NH4)2COO and 8 from 4H2O). Add a coefficient of 5 in front of CO2 to balance the oxygen atoms.
CH3COOH + (NH2)2CO → (NH4)2COO + 5CO2 + 4H2O

So, the balanced equation for the reaction between ethanoic acid and urea is:
CH3COOH + (NH2)2CO → (NH4)2COO + 5CO2 + 4H2O