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September 30, 2014

September 30, 2014

Posted by **anony** on Saturday, March 20, 2010 at 4:33pm.

there is a 53% chance that the child becomes infected with the disease. Suppose a female carrier of the gene has

three children. Assume that the infections of the three children are independent of one another. Find the

probability that all three of the children get the disease from their mother.

I don't really need an answer persay. I am trying to figure out a formula or how to figure out this problem for the most part because I am confused!

- Math/157 -
**bobpursley**, Saturday, March 20, 2010 at 4:58pmpr= .53*.53*.53

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