Posted by **Luricela** on Saturday, March 20, 2010 at 4:20pm.

An athlete whirls a 7.50-kg hammer tied to the end of a 1.1-m chain in a horizontal circle. The hammer moves at the rate of 1.3 rev/s.(a) What is the centripetal acceleration of the hammer?(b) What is the tension in the chain?

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**bobpursley**, Saturday, March 20, 2010 at 5:05pm
acceleration= w^2 r= (1.3*2PI rad/sec)^2 1.1m

tension= masshammer*acceleration

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**Luricela**, Saturday, March 20, 2010 at 5:35pm
Acctually i just found the answer for the acceleration, its similar to what you said except that you don't square it.The tension is (mass)(acceleration).

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**bobpursley**, Saturday, March 20, 2010 at 6:01pm
well, it is nice to know I have been doing it wrong, apparently, for 50 years.

I see here in Canada they are doing it my way also. Well, they are Canadians.

http://theory.uwinnipeg.ca/physics/circ/node6.html

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**MathMate**, Saturday, March 20, 2010 at 9:33pm
Could it be that I've been doing it wrong for the past 40+ years too, unless of course there is a not-so-minute chance that the textbook answer is wrong?

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**Luricela**, Sunday, March 21, 2010 at 11:14am
no its just that this is in revolutions per second (goes around the whole circle) when it should be redious per second. most questions just give it in seconds so it would be correct the other way (unless of course it is given in revolutions per second like in this problem).

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