Posted by **Jennifer** on Saturday, March 20, 2010 at 3:42pm.

The maximum weight M that can be supported by a beam is jointly proportional to its width w and the square of its height h, and inversely proportional to its length L.

a. Write an equation that expresses this prportionality

b. Determine the constant of proportionality if a beam 4 in. wide, 6 in. high, and 12 ft long can support a weight of 4800 lb.

c. If a 10-ft beam made of the same material is 3 in. wide and 10 in. high, what is the maximum weight it can support?

So far, I've got the equation. It's M=k^2wh^2/L. I need help working out the problem.

- Math -
**bobpursley**, Saturday, March 20, 2010 at 4:12pm
M=k*wh^2/L

I dont know why you squared k, the constant.

4800=K*4*36*12 note units in*in^2*ft

k=100/36

M=100/36*3*100*10=100,000/36=?

- Math -
**jane**, Friday, April 1, 2016 at 11:06am
the weight that a beam can support varies inversly as the length,suppose a 12 foot beam can support 12000 pounds how many pounds can a 15 foot beam support

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