posted by Jess on .
An 7.95 g bullet is fired horizontally into a 9.03 kg block of wood on an air table and is embedded in it. After the collision, the block and bullet slide along the frictionless surface together with a speed of 11.6 cm/s. What was the initial speed of the bullet?
Use the law of conservation of momentum to relate the velocity V' of the block (with embedded bullet) after impact, and the velocity of the bullet before impact, V.
0.00795 V = (9.03 + 0.0008)*V'
You already know V'. Solve for V.