How much copper could be produced if 5.00g of iron was used with 16.00g of copper (II) sulfate pentahydrate?

Write the equation and balance it.

Convert5.00 g Fe to mols. moles = g/molar mass.

Using the coefficients in the balanced equation, convert moles Fe to moles Cu.

Convert moles Cu to grams Cu. g = moles x molar mass.

To determine the amount of copper that could be produced, we need to set up and solve a stoichiometry problem.

First, we need to write a balanced chemical equation for the reaction between iron and copper (II) sulfate pentahydrate. The equation is as follows:

Fe + CuSO4·5H2O -> Cu + FeSO4 + 5H2O

From the balanced equation, we can see that 1 mole of iron reacts with 1 mole of copper to produce 1 mole of copper (Cu). We need to calculate the moles of iron and copper (II) sulfate pentahydrate to determine the limiting reagent and then use that information to determine the moles of copper produced.

To calculate the moles of iron, we can use the molar mass of iron (Fe), which is 55.85 g/mol.

Moles of iron = mass of iron / molar mass of iron
Moles of iron = 5.00 g / 55.85 g/mol

To calculate the moles of copper (II) sulfate pentahydrate, we can use the molar mass of CuSO4·5H2O, which is 249.69 g/mol.

Moles of copper (II) sulfate pentahydrate = mass of copper (II) sulfate pentahydrate / molar mass of copper (II) sulfate pentahydrate
Moles of copper (II) sulfate pentahydrate = 16.00 g / 249.69 g/mol

Now, we compare the moles of iron and copper (II) sulfate pentahydrate to see which substance is limiting. The limiting reagent is the one that will be completely consumed and determines the maximum amount of product that can be formed.

From the balanced equation, we can see that the ratio of moles of iron to moles of copper is 1:1. Therefore, if the number of moles of iron is greater than the number of moles of copper (II) sulfate pentahydrate, iron is the limiting reagent. On the other hand, if the number of moles of copper (II) sulfate pentahydrate is greater, copper (II) sulfate pentahydrate is the limiting reagent.

Finally, using the mole ratio from the balanced equation, we can calculate the moles of copper that can be produced.

Moles of copper = Moles of limiting reagent (either iron or copper (II) sulfate pentahydrate) * 1 mole of copper / 1 mole of limiting reagent (either iron or copper (II) sulfate pentahydrate)

Once we have the moles of copper, we can convert it to grams using the molar mass of copper (Cu), which is 63.55 g/mol.

Mass of copper = Moles of copper * molar mass of copper

By following these steps and performing the calculations, you will determine the amount of copper that could be produced from the given reactants.