Posted by **TRACY-888** on Saturday, March 20, 2010 at 3:39am.

how do you find the horizontal and vertical assymptotes of the curve

y= x/ x+3 and also the intercepts.

so that you can approximate the area under the curve from x=1 to x=5 using 5 function values?

THANKYOU,

- Maths 2U -
**drwls**, Saturday, March 20, 2010 at 9:31am
There is a vertical asymptote at x = -3 and a horizontal asymptote of y = 1, as x approaches + or = infinity.

The x-intercept is where x = 0, which would be y = (0,0). The y intercept would be where y = 0, or (also) (0,0). There is ony one intercept.

To approximate the area uner the curve, use the trapezoidal or Simpson's rule. and computed values of f(x) at x = 1,2,3,4 and 5. These values are 1/4, 2/5, 1/2, 4/7 and 5/8.

- Maths 2U -
**bobpursley**, Saturday, March 20, 2010 at 9:33am
What happens to the function as x>>-3 ?

What happens to the function as x>>inf

What happens to the function as x>>-inf

appx area. I am not certain of the technique you have been taught.

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