Wednesday

November 26, 2014

November 26, 2014

Posted by **TRACY-888** on Saturday, March 20, 2010 at 3:39am.

y= x/ x+3 and also the intercepts.

so that you can approximate the area under the curve from x=1 to x=5 using 5 function values?

THANKYOU,

- Maths 2U -
**drwls**, Saturday, March 20, 2010 at 9:31amThere is a vertical asymptote at x = -3 and a horizontal asymptote of y = 1, as x approaches + or = infinity.

The x-intercept is where x = 0, which would be y = (0,0). The y intercept would be where y = 0, or (also) (0,0). There is ony one intercept.

To approximate the area uner the curve, use the trapezoidal or Simpson's rule. and computed values of f(x) at x = 1,2,3,4 and 5. These values are 1/4, 2/5, 1/2, 4/7 and 5/8.

- Maths 2U -
**bobpursley**, Saturday, March 20, 2010 at 9:33amWhat happens to the function as x>>-3 ?

What happens to the function as x>>inf

What happens to the function as x>>-inf

appx area. I am not certain of the technique you have been taught.

**Answer this Question**

**Related Questions**

Math - How do you find the vertical and horizontal assymptotes of the graph of ...

Calculus - Find the area cut off by x+y=3 from xy=2. I have proceeded as under: ...

Calculus ll - Improper Integrals - Find the area of the curve y = 1/(x^3) from x...

calculus help - Find the points where the tangent line is horizontal or vertical...

calculus -- PLEASE HELP! - 1. There is a wall that does not need fencing [at x=0...

CALC - area under a curve - You have an unknown function that is monotone ...

calculus help please - Find the points where the tangent line is horizontal or ...

Python programming - A standard problem in mathematics is to measure the area ...

Calculus - 1. Find the area of the region bounded by the curves and lines y=e^x ...

Calculus - Hi there,could you help me with the following questions; 1.) Analyze ...