Posted by Val on Friday, March 19, 2010 at 8:16pm.
All you have to do is find the concentration of OH- and solve for pH (pOH= -log [OH-] nad then 14-pOH=ph
[OH-} = Ksp/[M+}
I agree with Trixie. I think the pH is about 4 (note that the ppt is forming WHEN the pH is ACID).
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